5x^2+27x+10=10

Solution for 5x^2+27x+10=10 equation:

5x^2+27x+10=10

We move all terms to the left:

5x^2+27x+10-(10)=0

We add all the numbers together, and all the variables

5x^2+27x=0

a = 5; b = 27; c = 0;
Δ = b2-4ac
Δ = 272-4·5·0
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-27}{2*5}=\frac{-54}{10}
=-5+2/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+27}{2*5}=\frac{0}{10}
=0
$